4n^2-19n+21=0

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Solution for 4n^2-19n+21=0 equation:


Simplifying
4n2 + -19n + 21 = 0

Reorder the terms:
21 + -19n + 4n2 = 0

Solving
21 + -19n + 4n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(7 + -4n)(3 + -1n) = 0

Subproblem 1

Set the factor '(7 + -4n)' equal to zero and attempt to solve: Simplifying 7 + -4n = 0 Solving 7 + -4n = 0 Move all terms containing n to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -4n = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -4n = 0 + -7 -4n = 0 + -7 Combine like terms: 0 + -7 = -7 -4n = -7 Divide each side by '-4'. n = 1.75 Simplifying n = 1.75

Subproblem 2

Set the factor '(3 + -1n)' equal to zero and attempt to solve: Simplifying 3 + -1n = 0 Solving 3 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1n = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1n = 0 + -3 -1n = 0 + -3 Combine like terms: 0 + -3 = -3 -1n = -3 Divide each side by '-1'. n = 3 Simplifying n = 3

Solution

n = {1.75, 3}

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